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6x^2=-108x+480
We move all terms to the left:
6x^2-(-108x+480)=0
We get rid of parentheses
6x^2+108x-480=0
a = 6; b = 108; c = -480;
Δ = b2-4ac
Δ = 1082-4·6·(-480)
Δ = 23184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{23184}=\sqrt{144*161}=\sqrt{144}*\sqrt{161}=12\sqrt{161}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(108)-12\sqrt{161}}{2*6}=\frac{-108-12\sqrt{161}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(108)+12\sqrt{161}}{2*6}=\frac{-108+12\sqrt{161}}{12} $
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